become expert | help | login
refer a friend - earn nickels!!
 advanced
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: a cyclotron is operating with a flux density of 3wb/m^2. the ion which enters the field is a proton
Forum Index -> Magnetism -> View Full Question originally posted here on IIT-JEE / AIEEE community   
Email  
Author Message
akki ~~ unlucky forever ~~ (1635)

Olaaa!! Perrrfect answer. 275  [405 rates]

akki ~~ unlucky forever ~~'s Avatar

total posts: 491    
Offline

flux density = magnetic field = 3 T

 

R(max) = 0.5m

 

we have,

 

R = mv/(qB)

 

v(max) = R(max)qB/m

 

KE(max) = (mv2)/2   (we can only find max KE with this data)

 

T(time period) = 2.pi.m/(qB)

 

period of half cell = pi.m/(qB)

 

just put values & get the ans...

 

 


all's well that end's well, but if it dosen't, then it is not the end . . .
  this reply:   12 points  (with Olaaa!! Perrrfect answer.   in 3   votes   )     [?]
 
You have to be logged on to rate
  
 
Sponsored Links
Free Exam Papers ?
unit, model, solved papers
IIT, Medical, CBSE. Get Free Now!

vriti.com/Scholarship