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Integration Theory
Tags: CBSE Board  |  Mathematics  |  Integral Calculus  |  Indefinite Integral  |  Definite Integral  |  Area Under Curve
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Introduction

Indefinite Integration

Basic Concept
Let F(x) be a differentiable function of x such that . Then F (x) is called the integral of f(x). Symbiotically, it is written as
f (x), the function to be integrated is called the integrand.
F(x) is also called the anti-derivate (or primitive function) of f (x).

Constant of Integration:
As the differential coefficient of a constant is zero, we have

This constant c is called the constant of integration and can take any real value.

Properties of Indefinite Integration


Basic Formulae













Method of Integration:
If the integrand is not a derivative of a known function, then the corresponding integrals cannot be found directly. In order to find the integral of complex problems, generally three rules of integration are used.

  • Integration by substitution or by change of the independent variable.
  • Integration by parts.
  • Integration by partial fractions.

Integration by substitution

   There are following types of substitutions

 

  • Direct Substitution

–– If integral is of the form , then put

g

(

x

) =

t

, provided  exists

 

  

  • Standard Substitutions
  • For terms of the form x2 + a2  or  put x = a tan   or   a cot
  • For terms of the form x2 - a2   or    put  x = a sec    or  a cosec
  • For terms of the form a2 - x2   or  put  x = a sin   or  a cos
  • If both  are present then put  x = a cos
  • For the type   put  x = a cos2 + b sin2 
  • For the type put the expression within the bracket = t
  • For the type   put 
  • For again put (x + a) = t (x + b)
  • Indirect Substitution

–– If the integrand is of the form

f

(

x

)

g

(

x

), where

g

(

x

) is a function of the integral of

f

(

x

), then put integral of

f

(

x

) =

t

.

 

e.g.   Evaluate

Sol.   Integral of the numerator =

   Put   

x3/2

 =

t

   We get

l

=

  • Derived Substitution:

–– Some time it is useful to write the integral as a sum of two related integrals which can be evaluated by making suitable substitutions.

 

   Examples of such integrals are:

 

   A. Algebraic Twins

 

    



    



Method:

* Make the integration in the form

 

    

   or

*If

  is present then put

If

 is present then put 



B. Trigonometric twins

    

    

    



Integration by Parts

1.     If

u

and

v

be two function of

x

, then integral of product of these two functions is given by




Note:

In applying the above rule care has to be takne in the selection of the first function (

u

) and the second function (

v

). Normally we use the following methods:

 

(

i

)     If in the product of two functions, one of the functions in not directly integrable (

e.g.

sin

-1x

, cos

-1x

, tan

-1

 

x

etc.) then we take it as the first function and the remaining function is taken as the second function

e.g.

In the integration

x tan

-1x

dx, tan

-1

x is taken as the first function and

x

as the second function.

 

(

ii

)    If there is no other function, then unity is taken as the second function

e.g.

In the integration of  

tan

-1x

dx, tan

-1

is taken as the first function and 1 as the second function.

 

(

iii

)   If both of the function are directly integrable then the first function is chosen in such a way that the derivative of the function thus obtained under integral sign is easily integrable. Usually we use the following preference order for the first function  (inverse, Logarithmic, Algebraic, Trigonometric, Exponential)

 

In the aove stated order, the function on the left is always chosen as the first function. This rule is called as ILATE

e.g.

In the integration of  

x sin x dx, x is taken as the first function and sin

x

is taken as the second function.



Important Result:
*

In the integral , if  

g

(

x

) ex dx, if g(x) cna be expressed as

g

(

x

) =

f

(

x

) +

f

'(

x

)

 

then

Some times to solve integral of the form

 we write it as

and solve the integral with the help of integration by parts, taking

  as the first function.


e.g.

 

is solved by writting it as

 

 

 and this integral can be solved by parts.




Algebraic Integrals

I. Integral of the form

In these types of integrals we write

px + q

=

l

(diff. coefficient of

ax2

 +

bx + c

) +

m

Find

l

and

m

by comparing the coefficient of

x

and constant term on both sides of the identify. In this way the question will reduce the sum of two integrals which can be integrated easily.

 

Integral of the type

In this case substitute

ax2

 +

bx + c

=

M

(

px2

 +

qx + r

) +

N

(2

px

+

q

) +

R

Find

M, N

and

R

. The integration reduces to integration of three independent functions.



II.     Integration of Irrational Algebraic Fractions

1.     Rational fucntion of (

ax + b

)

1/n

 and

x

can be easily evaluated by the substitution

tn = ax + b

. Thus

2.     In the integration of

 the substitution

x - k

= 1

/t

reduces the integration

 to the problem of integrating an expression of the form

3.     .

 Here we substitute,

x - k

= 1/

t

.

 

This substitution will reduce the given integral to

4.     To integrate

 we first put

x

= 1/

t

, so that

 

–––––––––––

Now the substitution

C

+

Dt2

 =

u2

  reduces it to the form 


III. Integration of the function of the type

,

Where m, n, p are rational numbers

 

This integral is expressed through elementary functions only if one of the following conditions is fulfilled:

 

(1)     If p is an integer,

 

(2)     If

 is an intger,

 

(3)     If

 + p is an integer.

 

  

1st case :

(a)     If p is a positive integer, remove the brackets (a + bxn)p according to the Newton binomial and calculate the integrals of powers.

 

(b)     If p is a negative integer, then the substitution x = tk, where k is the common denominator of the fractions m and n, leads to the integral of a rational fraction;


2nd case :

If

 is an integer, then the substitution a + bx

n

 = t

k

 is applied, where k is the denominator of the fraction p;



3rd case :

If

 + p is an integer, then the substitution a + bx

n

 = xnt

k

 is applied, where k is the denominator of the fraction p.


Example :

(i)

(ii) 

 

 

(iii)   

  

 

(iv)

 


Trignometric Integrals
I. Integral of the form

Universal substitution tan .

In this case sin

x

=

;  cos

x

,  

x

= 2 tan- 1 

t

dx

=

   If R (- sin x, cos x) = - R (sin x, cos x), then the substitution cos x = t is applied.

 

   If R (sin x, - cos x) = - R (sin x, cos x), then the substitution sin x = t is applied.

 

   If R (- sin x, - cos x) = R (sin x, cos x), then the substitution tan x = t is applied.


II.  Integral of the form

(i)

   

 

(ii)   

dx

 

(iii)   

dx    

 

(iv)   

This type of integration can be solved by converting the Nr in the form Nr = P(Dr) + Q + R the value of P, Q, R can be findout by comparing the coeffcient of both sides.



III. Integral of the form

(i)

(ii)   

  (iii) 

Transform the product of trigonometric function into a sum or difference, using one of the following formulas:

 

sin ax sin bx =  [cos(a-b) x - cos (a+b)x]

 

cos ax cos bx =  [cos (a - b) x + cos (a + b) x]

 

sin ax cos bx =  [sin (a - b) x + sin (a + b) x]

 

IV.     Integral of the form

 , where m and n are integers.

 

(i) If m is an odd positive number, then apply the substitution cos x = t.

 

(ii)     If n is an odd positive number, apply the substitution sin x = t.

 

(iii)    If m and n are even non-negative numbers, use the formulas

 

    

(iv)    

  where (o <

x

< ?/2) and

p

and

q

are rational numbers.

 

     Substitute sin

x

= t

 

    



V.    Integral of the form

 

 when

VI.    Integral of the form

(i)

     (ii)

(iii)   

    (iv)

  

 

This type of integration can be solved by multiplying sec

2

x, in N

r

 and D

r

  and substituting tan x = t, or cot x = t.



VII.    Integral of the form

(i)

     (ii)

   (iii)

To solve this type of integration

 

1) convert sinx and cosx in terms of tan x/2 by putting.


2) Write N

r

 in the form sec

2

 x/2 and Dr in the form tan x/2.

 

3) Substitute tan x/2 = t, so that sec

2

x/2 dx = 2dt



VIII.

  If D

r

is in the form K + L sin x cos x, then Nr must be in the form of sin x + cos x, or sin x - cos x.

 

(1)     If N

r

 has sin

x

+ cos

x

then substitute sin

x -

cos

x

=

t

    

(cos

x

+ sin

x

)

dx = dt

(2)    

Nr

 has sin

x

- cos

x

then substitute sin

x

+ cos

x

=

t

    

(cos

x

- sin

x

)

dx = dt

Note: If sin

x

- cos

x

=

t

    1 - sin 2

x

=

t2

    

   sin 2

x

= 1 -

t2

   If sin

x

+ cos

x

=

t

    1 + sin 2

x

=

t2
        

sin 2

x

=

t2

 - 1



INTEGRATION BY Partial fraction

   Let 

  is a proper algebric function.

 

   The partial fractions depend on the nature of the factors of

Q

(

x

). We have deal with the following different type when the factors of

Q

(

x

) are

 

   (i) Linear and non-repeated

 

   (ii)  Linear and repeated

 

   (iii) Quadratic and non-repeated

 

   (iv) Quadratic and repeated



Case I :

 When denominator is expressible as the product of non-repeated linear factors :

 

Let Q (x) = (x - a

1

) (x - a

2

) (x - a

3

) ... (x - a

n

).

 

Then we assume that ;


where A

1

, A

2

, ...., A

n

 are constants and can be determined by equating numerator on R.H.S to numerator on L.H.S. and then substituting x = a

1

, a

2

, .... a

n

,



Case II :

When the denominator

Q

(

x

) is expressible as the product of the linear factors such that some of them are repeating. (Linear and Repeated)

 

Let, Q(x) = (x-a)

k

 (x-a

1

) (x-a

2

) ... (x-a

r

). Then we assume that

 

 



Case III :

When some of the factors in denominator are quadratic but non-repeating.

 

Corresponding to each quadratic factor ax

2

 + bx + c, we assume the partial fraction of the type

, where A and B are constants to be determined by comparing coefficients of similar powers of x in numerator of both sides.



Case IV :

When some of the factors of the denominator are quadratic and repeating. For every quadratic repeating factor of the type (ax

2

 + bx + c)

k

, we assume :


Short cut Method of Finding the Constant of a Non-repeated Linear Factor in Denominator

 

Let   

 

    

    

    

 

    

    

    

    

    



Definite Integrals

1.  If f and F are two continuous functions defind on [a, b] such that

then the number

 

F(b) - F(a) is called definite integration of f between a and b and is denoted by 

i.e., 

This is called fundamental theorem of integral calculus. Here 'a' is called lower limit (LL) and 'b' is upper limit (U.L) and

 always.

 

Also

 

dx

denotes algebric sum of the area bounded by curve

y

=

f

(

x

) , ordinates

x = a, x = b

and

x -

axis.

 

2. 

is always unique.

 

  •  is also defined as an infinite limit sum..   

4. 


Properties of Definite Integration:

1. 

2.

3. 

where a < c < b

 

4. 

but converse need not be true

 

5. 

6. 

7. 

8. 

9. 

10.   

If  but converse need not be true.

 

11.   

If  but converse need not be true.

 

12.   

(change limit Theorem)

 

13.   

14.   

15.   

16.   

17.   

18.   

 This is called

Leibnitz rule

.

 

19.   

where m and M are respectively the minimum and maximum values of

f

(

x

) in [

a, b

]

 

20.    If f is a periodic function with period

T

, i.e., if

f

(

x + T

) =

f

(

x

) then

 

   a)

   b)

   c)

 where m, n are integers

 

   d) 

  i.e., it is not dependent on 'a'

 

21.   

This is called cauchy - schwartz inequality



WALLI'S FORMULAE :

 


22.       
23.   
   Case (1)

: If m is odd and n is either even or odd

 

  

  

Case (2)

: If m is even and n is even

 

  

  

Case (3)

: If m is even and n is odd.

 

  



Reduction Formulae on Definite Integration

:

 

24.    If 

  then  

   (where n > 2)

 

25.    If 

 then  

26.    If 

 then 

27.    If 

 then

 

 

28.   

By parts Formulae on Definite Integration :
  

29.    If a function has finite number of points of discontinuties in [a, b] then the function is definite integrable in that interval.

 

30.   

Definite integration as infinite limit sum :

1)

2)

Working rule :

   

Step I

: First reduce the given infinite limt into the form  

   

Step II

: Replace r/n with x and 1/n with dx

 

   

Step III

: Replace

 

  

 

  


Note :

1) 

   2)

   3) 

:




   

 
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